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Rectangles mein ek Khoj

Class 6 Maths · Chapter 8: Constructions se Khel · NCERT Ganita Prakash section 8.4

Seekho

Ye paheli Sahil ko mili. Rectangle ABCD lo jisme AB = 7 cm aur BC = 4 cm. Point X, AD bhuja par kahin bhi khisak sakta hai, aur point Y, BC par kahin bhi. X aur Y ko jodo.

Pehle andaaza lagao: XY ko sabse chhota banane ke liye X aur Y kahan hon? Aur sabse lamba? Andaaze likho, phir jaancho.

Ek table koshishon ka hisaab rakhti hai: A se X ki doori, B se Y ki doori, aur XY ki lambai. Jab pehle do number barabar hon tab ek pattern dikhega.

Jab AX = BY, XY seedha hota hai aur AB = 7 cm ke barabar: sabse chhota. XY sabse lamba tab hai jab X aur Y ulte konon par hon (X, A par aur Y, C par, ya X, D par aur Y, B par): tab XY diagonal hai.

Explore: X aur Y khiskaao aur XY ki lambai dekho.

  1. XY ko sabse chhota banao.
  2. Ek alag jagah dhoondo jo utni hi chhoti ho.
  3. Ab XY ko sabse lamba banao.

Yaad rakho

  • XY sabse chhota (AB ke barabar) tab hai jab X aur Y, A aur B se barabar door hon.
  • XY sabse lamba tab hai jab wo rectangle ka diagonal ho.

Quick check

Upar wale rectangle mein AX = 3 cm aur BY = 3 cm. XY kitna lamba hai?

  1. 7 cm
  2. 3 cm
  3. 4 cm
  4. 10 cm
Answer

7 cm. X aur Y barabar neeche hain, to XY seedha hai aur AB = 7 cm ke barabar.

Socho

Kya XY kabhi AB se chhota ho sakta hai? Samjhaao.

Ek answer

Nahi. X hamesha baayein bhuja par aur Y daayein par hai, aur rectangle ko ek bhuja se doosri tak paar karne ka sabse chhota raasta seedha paar hai, jo AB ki lambai hai.

Practice

Teen levels (easy, medium, hard) ke naye sawaalon se practice karo, kuch hands-on, hints aur hal ke saath. Topic poora karne ke liye pichhle 5 mein se 4 sahi karo.